2/1+6/1+12/1+...90/1+110/1+132/1的值是多少?

Answer 1

1/2+1/6+1/12+.....+1/90+1/110+1/132
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+....+(1/9-1/10)+(1/10-1/11)+(1/11-1/12)
=1-1/12
=11/12

Answer 2

是不是1/2+1/6+...1/132;
是的话，原式=(1-1/2)+(1/2-1/3)...+(1/11-1/12)
=1-1/12
=11/12

Answer 3

12/11