理工学科-化学：关于消去反应

Question

BrCH2CH2Br+NaOH 的醇溶液反应方程式
BrCH2CH2Br+2NaOH 的醇溶液

注意氢氧化钠的系数，这个怎么写

Answer 1

BrCH2CH2Br+NaOH== BrCH=CH2+NaBr+H2O
BrCH2CH2Br+2NaOH ==CH≡CH+2NaBr+2H2O

箭头，上面条件略

Answer 2

BrCH2CH2Br+NaOH ==CH2═CH—Br+NaBr+H2O (消去1分子HBr)
BrCH2CH2Br+2NaOH ==CH≡CH+2NaBr+2H2O (消去2分子HBr)

等号是箭头

Answer 3

BrCH2CH2Br+NaOH =BrCH=CH2+NaBr+H2O
-------------------有烯键
BrCH2CH2Br+2NaOH=C2H2+2NaBr+2H2O
------------------乙炔